God, so hard to tell with angles, foreshortening, etc... but I'm guessing at least 40ft.
It was a perfect throw. All the kvetching about Moore misplaying the ball ignores that Jones misplayed it as well. I mentioned it on another thread.
Jones turns his body so he's facing the defender, which would have given Moore a chance to get his arm in there if he'd played Jones instead of trying to play the ball. I don't blame Jones- I don't know that he's capable of making the over-the-shoulder catch like we saw Boldin do against the Irsays- but it is what it is. The way Flacco threw that ball, if Jones plays it right the only chance either DB has of stopping the catch is to interfere with Jones. That ball nearly dropped straight down into his arms. That's awful tough to defend.
If there's another QB in the league capable of making that throw, I haven't seen him do it.
Ran a couple of calculations. Using 3.2 seconds as the hang time (which is what I calculated with a stop watch, but someone else just verified) and the 59 yards traveled estimate, I calculated an initial velocity of the throw at 23.02 meters/second (which is roughly 52 mph). Using that, I got a 42.92 degree launch angle. Also, the peak height came out to be 12.5 meters (13.7 yards).
If anyone has any theories as to how to use these numbers to get a distance of a curve, feel free. I have no idea.
But it will be hard because it's hard to determine how many yards the ball sailed to the right.
EDIT: Oh, you mean including height and stuff. Oops.
This is the greatest and funniest thread I have ever seen. Love it.
Didn't the Ravens hire a numbers guru. Maybe he could chime in. :)
but I used the 54 yds distance.
Comes up with an arc of 202' 3 3/8".
(a little over 67 1/3 yds.)
I dunno,I could have messed it up.
OMG Thread of the WEEK. LOL
So assuming the vertical displacement is negligible, we have a distance traveled of 49 meters in a time of 3.2 seconds.
We can calculate vertical velocity by using
0 = (initial velocity)(3.2) + 1/2 ( -9.8) (3.2^2)
This comes out to an initial vertical velocity of 15.68 m/s
We can then approximate max height using
0 = 15.68^2 - 2 (-9.8)(max height)
This gives us a max height of ~ 12.544 meters or about 36 feet
Initial horizontal velocity can be calculated using
49 = x(3.2) + 1/2* -.1 * (3.2^2)
This gives us an initial horizontal velocity of approximately 15.475 m/s
Using the calculated stuff here, we can use the following:
Integral from 0 to 3.2 of
sqrt((15.47 - .1t)^2 + (15.68 - 9.8t)^2)
Which gives us an arc length of 74.551 meters, or approximately 81 yards.
Pretty awesome. Note these are rough figures, since we can't really be completely precise with the information we have
BaltimoreBoy - Do yourself a favor and email that to ESPN/sports science with emphasis on whether Moore could have made that play. That would be a sweet segment and I can't recall an episode where they focused on ball distance / height.
This thread will end poverty and end all wars.