The Arc on Joe's ball.

[RedSkins Fury]

Height's a little tough to tell.
35' maybe?

God, so hard to tell with angles, foreshortening, etc... but I'm guessing at least 40ft.

[Baltimoreboy]

Tell me how long the ball was in the air, as accurate as possible, and I'll tell give you my best guess as to how far it traveled.

I get 96 frames on the player with a frame rate of 29.970628.

Comes out to about 3.2 seconds.

[LukeDaniel]

That throw was about as perfect as one can throw the ball 60 yards in the air, on the run. No other QB in the NFL could have made that throw, that distance, with that much air under it and not even being able to fully step into his throw.

That is why is was completed. Moore had no idea that the ball could be thrown that far, and it surprised him.

This was exactly my assessment of it. Moore was the goat, but I think he wouldn't have been the only one, in a similar situation, to make the same mistake. That ball just never seemed to lose trajectory. Sorta like a ball that keeps carrying over a centerfielders head.

[bacchys]

It was a perfect throw. All the kvetching about Moore misplaying the ball ignores that Jones misplayed it as well. I mentioned it on another thread.

Jones turns his body so he's facing the defender, which would have given Moore a chance to get his arm in there if he'd played Jones instead of trying to play the ball. I don't blame Jones- I don't know that he's capable of making the over-the-shoulder catch like we saw Boldin do against the Irsays- but it is what it is. The way Flacco threw that ball, if Jones plays it right the only chance either DB has of stopping the catch is to interfere with Jones. That ball nearly dropped straight down into his arms. That's awful tough to defend.

If there's another QB in the league capable of making that throw, I haven't seen him do it.

[dandrews]

Ran a couple of calculations. Using 3.2 seconds as the hang time (which is what I calculated with a stop watch, but someone else just verified) and the 59 yards traveled estimate, I calculated an initial velocity of the throw at 23.02 meters/second (which is roughly 52 mph). Using that, I got a 42.92 degree launch angle. Also, the peak height came out to be 12.5 meters (13.7 yards).

If anyone has any theories as to how to use these numbers to get a distance of a curve, feel free. I have no idea.

[PurpleApocalypse37]

That would be a good one for a math guy..... There must be some equation based on the distance, height, angle. The height alone has to almost double the distance the ball went compared to ball thrown on a rope. I'm not a calculus guy... lol.

More impressive is that the bail didn't hang... it still had a ton of velocity. Is Sports Science on this?

And, I think Moore was in position for a standard deep throw. It was the arc that put it over his head. Moore misplayed the arc, not the distance.

Haha it only takes pre-Algebra to calculate. Just draw a triangle from where Flacco was when he threw the ball, to where Jacoby was when he caught the ball, and then draw a straight line back to where Flacco was when he threw it, and then finish connecting the dot. Then just do the Pythagorean theorem.

But it will be hard because it's hard to determine how many yards the ball sailed to the right.

EDIT: Oh, you mean including height and stuff. Oops.

[zckattk]

This is the greatest and funniest thread I have ever seen. Love it.

[Roland of Gilead]

Haha it only takes pre-Algebra to calculate. Just draw a triangle from where Flacco was when he threw the ball, to where Jacoby was when he caught the ball, and then draw a straight line back to where Flacco was when he threw it, and then finish connecting the dot. Then just do the Pythagorean theorem.

But it will be hard because it's hard to determine how many yards the ball sailed to the right.

EDIT: Oh, you mean including height and stuff. Oops.

I estimated the distance to the right as the distance from the hash to the sideline (the ball was thrown from and caught within a yard of two of each). Knowing that the has marks are 18.5 feet apart and the width of the field is just over 53 yards (2x+18.5=160), I estimated the short leg of the right triangle to be 24 yards. That's what gave me the 59 yards total.

[Kyle Cactus]

Didn't the Ravens hire a numbers guru. Maybe he could chime in.

[Baltimoreboy]

This is the greatest and funniest thread I have ever seen. Love it.

I think some of us are bored,something to do

Ran a couple of calculations. Using 3.2 seconds as the hang time (which is what I calculated with a stop watch, but someone else just verified) and the 59 yards traveled estimate, I calculated an initial velocity of the throw at 23.02 meters/second (which is roughly 52 mph). Using that, I got a 42.92 degree launch angle. Also, the peak height came out to be 12.5 meters (13.7 yards).

If anyone has any theories as to how to use these numbers to get a distance of a curve, feel free. I have no idea.

I just use something like Sketchup,it does all the figuring.
but I used the 54 yds distance.
Comes up with an arc of 202' 3 3/8".
(a little over 67 1/3 yds.)
I dunno,I could have messed it up.

[RavensQB]

OMG Thread of the WEEK. LOL

[RedSkins Fury]

I think some of us are bored,something to do



I just use something like Sketchup,it does all the figuring.
but I used the 54 yds distance.
Comes up with an arc of 202' 3 3/8".
(a little over 67 1/3 yds.)
I dunno,I could have messed it up.

Hellz Yeah! Thank you!

[CptJesus]

So assuming the vertical displacement is negligible, we have a distance traveled of 49 meters in a time of 3.2 seconds.

We can calculate vertical velocity by using

0 = (initial velocity)(3.2) + 1/2 ( -9.8) (3.2^2)

This comes out to an initial vertical velocity of 15.68 m/s

We can then approximate max height using

0 = 15.68^2 - 2 (-9.8)(max height)

This gives us a max height of ~ 12.544 meters or about 36 feet

Initial horizontal velocity can be calculated using

49 = x(3.2) + 1/2* -.1 * (3.2^2)

This gives us an initial horizontal velocity of approximately 15.475 m/s

Using the calculated stuff here, we can use the following:

Integral from 0 to 3.2 of
sqrt((15.47 - .1t)^2 + (15.68 - 9.8t)^2)

Which gives us an arc length of 74.551 meters, or approximately 81 yards.

Pretty awesome. Note these are rough figures, since we can't really be completely precise with the information we have

[Sirdowski]

BaltimoreBoy - Do yourself a favor and email that to ESPN/sports science with emphasis on whether Moore could have made that play. That would be a sweet segment and I can't recall an episode where they focused on ball distance / height.

[CptJesus]

BaltimoreBoy - Do yourself a favor and email that to ESPN/sports science. That would be a sweet segment and I can't recall an episode where they focused on ball distance / height.

I'm not sure if my calculations are off or theirs are, but we're getting 2 different values.

Also:

[Sirdowski]

I'm not sure if my calculations are off or theirs are, but we're getting 2 different values.

Also:

HAHAHA. funny stuff.

[Baltimoreboy]

I'm not sure if my calculations are off or theirs are, but we're getting 2 different values.

Yea,
82' high and an arc length of 380 yds sounds a little off

[dscola31]

This thread will end poverty and end all wars.

[CptJesus]

Yea,
82' high and an arc length of 380 yds sounds a little off

I messed up my integral, forgot the square root. The arc lenght is 31.63 meters, or approximately 34 yards.

[Baltimoreboy]

So assuming the vertical displacement is negligible, we have a distance traveled of 17.98 meters in a time of 3.2 seconds.

The ball traveled about 54 yds
(49.3776) meters.

Don't understand the rest